HomeMy WebLinkAboutB14-0240_Structural Calcs.PDF_1404935940.pdf Structural Calculations
For
VVMC Cath Lab
Vail, Colorado
SCI # 14-011-02
PREPARED FOR
Heery International
July 3, 2014
STRUCTURAL
CONSULTANTS
INCORPORATED
3400 E. Bayaud Avenue
Suite 300
Denver, Colorado 80209
({\\01) REC;
.L'I GO e cL 7`
■ V
I ;m 13819 ;� 4
:1/4c1
I ' .,- ..
STRUCTURAL Job Title V J/M 'C c 0Zf4 G'7 Job no. / V-°//-I-Z--
CONSULTANTS
INCORPORATED
Client /:r4' ' ` , By 4 Date 7/ //i Sheet of
/ _ .. /1 ; ./a/ 4 •. a1..�-raj�3 26745 �J2)/riF 2.L iCl P.
/
I ' ' / 1 I i
1
_--
— J�- �
+r 1Y-LY
if rr
Z., frn i .
.7,-,7,,,../,-,..c.-'t. L~�4x '1, a- w i ,z,_/ v2) j -7-- _ ' 2 c.e. FGF; o f,C ,$11 Oi
ql?'2. i j
:
I l
4.-444-5 nu`ri r =, : o "C. ' ,
, I
1---4- /sr .X 1/30 i •'? . :
r
r/7 (/t / -.....) . I ,-e: -7:1' I i I : i +
1 11 t
.,..--,6 - E„v� e-r'C.c d 7 • 5 �4.. 1 1 I
,,Tia/r7/A 4, r /7rL•� fl/'a/C': (1-S' ri f”)!•`/[rr94 r l L r X9-/7'4 .
E-C' Lr'rre�c'/3 c. et, I ' L E ] l I
1
Gd A,s'/n:r-A. 2 4-14' 'Lv 6 r9-e z- • e -e -- 4 ;.5 F
(-/ Cu -'2 .icrG' i ��C 9r1 A{" p
J C � � ICS/ t�eu ,��.. II [� /�`� �'' � �+•11�_ S�J���v
6,o P,SF: LL /r
/1�7 fJ u C�f'' !� �j v>r'�lam} ,f'�rY'[�� �'�i� I L urtr. 6---1.4,' or!
/--e- i, vr./ / 4'..k!Co ] Flej'• !f 0 r G: (' 14.'.- / . . I i j ,
1 I I i
1 1
i
3400 E.Bayaud,#300,Denver,CO 80209 303/399-5154 FAX 303/333-9501
STRUCTURAL Job Title f/(/MC- C 97/f 44-6 Job no./4/-0/-D z
CONSULTANTS
INCORPORATED Client t/e By ,4— Date 7/3//it Sheet of
,
Ir-E 11/C-,4-tf '‘.ti.4ra(/,4 u e(si-7 k---,,),)2"e0, 1){1--j ! "7). , 6-Fr,"12r (.2'-/` 4A •CL:6
! I
C4E4 51-.4 A,0 r'. , '7 - c57'4 rn?Pz/ter0; 7,a 4-4r.).' /ii$4;i•f7 '
d 1 ; I I 1
; i 1 i i [
P, *5 t V'0 7^�,z,A-' •/f irk' 2•!-K A i I ..ir . i 1
I I I i 1 ,
I 1 ,
7 ,r!" ' " Irk IJkt c ~
i - . 7 'fa,r I • i . i
} / sF I I • 1 j l E i i j
►..i 'K I ., I , i 1 ! , i i
I r I i I . .i ..
I i I . I !
{
'7;1- t_` f L . 1 C I : . I S'Ef1fr!S ri'/l ! 7d C'' ;764r6" % ; --.7-2. : ,/c-1/1-- .
i I ,
LP. 4.05. rN/I'(t•e. '7,i. Jr7r C: LL C1/':� /_SU/ryf)
I
?r p ft t L = 6 v /fpi I : •
I
I
D.L - . 2v Pd
.�'T/ r"..5F .4 /„co t-, r:--, ef/c . ,
I
7y Fly- z_L= ..-bPs =•
e4.4 LL. g.. TP- ;
IJ C f .r F ! :• e I
-
I. .. /J'fr[•,1 --' +' r',-F e1L • ,
I I
1 • 1
fCee l r /9(!)• 4.'r! : .4'1, -C ' •
' 1
I ,
4-0 /& 13 t6 00 •
/ 4_ 117 ' /` ii 17.5 I G..r� -r Zr /
� I �' ��P%�r;r 7� f ,
I
,;EL ire-- .C.4-Lc (Fe . fes p1,4 1 FJ Yl: /tis ot:. .1 '
1 1
i I •
3400 E.Bayaud,#300,Denver,CO 80209 303/399-5154 FAX 303/333-9501
a(
Concrete Beam ENERCALC,
ENERCALC,INC.1983-2014.Build:6.14.1.26,Ver:6.14.1.26
Lie.#7 KW-06002110 Licensee:STRUCTURAL CONSULTANTS,INC.
Description: Review capacity of(E)FJ 21
CODE REFERENCES
Calculations per
Load Combination Set :ASCE 7-02
Material Properties
f'c112 - 4.0 ksi 6 Phi Values Flexure: 0.90 a
fr= fc * 7.50 = 474.342 psi Shear: 0.750 • ■
m
yf Density = 145.0 pcf R 1 = 0.850
A, LtWt Factor = 1.0 - -
Elastic Modulus = 3,122.0 ksi Fy-Stirrups 40.0 ksi
fy-Main Rebar = 60.0 ksi E-Stirrups = 29,000.0 ksi
E-Main Rebar = 29,000.0 ksi Stirrup Bar Size#= # 3
Number of Resisting Legs Per Stirrup= 2 • •
Load Combination ASCE 7-02 ' 6 in
36 in '
O[0+>1 I L10 451
/ •
6"wx16.5'5
Span=19.50 ft
Cross Section&Reinforcing Details
Tee Section, Stem Width=6.0 in, Total Height=16.50 in,Top Flange Width=36.0 in, Flange Thickness=6.0 in
Span#1 Reinforcing....
2-46 at 1.30 in from Bottom,from 0.0 to 19.50 ft in this span 2-#5 at 1.30 in from Top,from 0.0 to 6.50 ft in this span
2-#6 at 1.30 in from Top,from 14.60 to 19.50 ft in this span
Applied Loads Service loads entered Load Factors will be applied for calculations.
Load for Span Number 1
Uniform Load: D=0.410, L=0.450 k/ft, Tributary Width=1.0 ft
DESIGN SUMMARY Desi•n OK
Maximum Bending Stress Ratio = 0.958: 1 Maximum Deflection
Section used for this span Typical Section Max Downward L+Lr+S Deflection 0.039 in Ratio= 5935
Mu :Applied -38.405 k-ft Max Upward L+Lr+S Deflection 0.000 in Ratio= 0<360
Mn*Phi :Allowable 40.074 k-ft Max Downward Total Deflection 0.058 in Ratio= 4021
Load Combination +1.20D+0.50Lr+1.60L+1.60H
Max Upward Total Deflection 0.000 in Ratio= 999<180
Location of maximum on span 0.000ft
Span#where maximum occurs Span#1
Cross Section Strength&Inertia Top&Bottom references are for tension side of section
Max Mu (k-ft) Phi*Mn (k-ft) Moment of Inertia (inA4)
Cross Section Bar Layout Description Bottom Top Bottom Top I gross Icr-Bottom Icr-Top
Section 1 2-#6 @ d=15.2",2-#5 @ d=1.3", 0.00 0.00 61.11 40.07 4,546.51 1,511.16 903.32
Section 2 2-#6 @ d=15.2", 0.00 0.00 59.34 0.00 4,546.51 1,505.15 2.78
Section 3 2-#6 @ d=15.2",2-#6 @ d=1.3", 0.00 0.00 61.36 56.29 4,546.51 1,513.50 1,192.55
Vertical Reactions-Unfactored Support notation:Far left is#1
Load Combination Support 1 Support 2
Overall MAXimum 8.309 8.461
Overall MINimum 3.998 3.998
D Only 3.998 3.998
L Only 4.388 4.388
D+L 8.309 8.461
Concrete BeamFile=C:1PR0GRA-21ENERCA-1
ENERCALC,INC.1983-2014,Build:6.14.1.26,Ver:6.14.1.26
tfe:-i4ts ifigh 002710 Licensee:STRUCTURAL CONSULTANTS,INC.
Description: Review capacity of(E)FJ 21
Shear Stirrup Requirements
Between 0.00 to 5.98 ft, PhiVc/2<Vu<=PhiVc, Req'd Vs=Min 11.4.5.1, use stirrups spaced at 7.000 in
Between 6.02 to 13.48 ft, Vu<PhiVc/2, Req'd Vs=Not Reqd, use stirrups spaced at 0.000 in
Between 13.52 to 19.46 ft, PhiVc<Vu, Req'd Vs=3.145, use stirrups spaced at 7.000 in
Overall Maximum Deflections-Unfactored Loads
Load Combination Span Max."2 Defl Location in Span Load Combination Max."+"Defl Location in Span
D+L 1 0.0582 9.555 0.0000 0.000
Maximum Deflections for Load Combinations -Unfactored Loads
Load Combination Span Max.Downward Defl Location in Span Max.Upward Defl Location in Span
D Only 1 0.0188 9.945 0 0000 0.000
D+L 1 0.0582 9.555 0.0000 0.000
D Only 1 0.0188 9.945 0.0000 0.000
L Only 1 0.0206 9.945 0.0000 0.000
D+L 1 0.0582 9.555 0.0000 0.000
20 - ;
5
OFAM•--=+
:.____..--- ' ..........„....:::.
.54
..-
39 n
1,91 3.86 5.81 7.76 9.71 11.66 13.61 15.56 17.51 19.46
Distance(ft)
■+1030 •+1.2OD+0,501,+1.611+1.608 •+1,200+1.631+0.505+1.608 •+1.200+1.613L,+0,561 ■+1-201+L6DL,+13.EDW f+1.2DD+D.SOL+1.665
■+1 20D+1 661+D 80W ■+1.20D+0.511,+6.561+1.60W■+1.2DD+0-501+0.565+1-6DW ■+1.20D+6.561+0,205+E ■+D-4DD+L•6DW+1.6DH ■+0.96D+E+1.608
I
SEA ..rr -
`m
•12 '_^+.r
1.91 3,86 5,81 7,76 9.71 11.66 13.61 15.56 17.51 19.46
Distance(ft)
■+106D ■+1 201+0.501,+1 601+1 608 •+1 2DD+1 601+0 505+1.6011 •+1.20D+1.601,+6.501 •+1.26D+L66L,+D.BDW IN+1 280+8 SDL+1 EDS
e+1 20D+1 605+0 8DW ■+1 211D+D SDL.+D 501+1 6DW•+1 266+6,561+0 501+1,60W •+1.261+6.SDL+6.2DS+E ■+13-46D+L66W+1.60H ■+D 901+E+1 101
BEAM---..
-0,015 - '��
-0.030 \\`0 _ ,� ,
O
-0.045 - ..... .I .
.0.059 [ w�...�
1.37 3.32 5.27 7.22 9.17 11.12 13.07 15.02 16.97 18.92
Distance(ft)
■D O.,ly■D+L■D Only IN L Only■D+L
Concrete Beam File=C:1PROGRA-21ENERCA--1
ENERCALC,INC.1983-2014,Build:6.14.1.26,Ver:6.14.1.26
Lic.#: KW-06002110 Licensee:STRUCTURAL CONSULTANTS,INC.
Description: Review capacity of(E)FJ 22
CODE REFERENCES
Calculations per
Load Combination Set :ASCE 7-02
Material Properties
f'c1/2 = 4.0 ksi d Phi Values Flexure: 0.90
fr= f'c * 7.50 = 474.342 psi Shear: 0.750 -
yf Density = 145.0 pcf 13 1 = 0.850
X LtWt Factor = 1.0 ` '
Elastic Modulus = 3,122.0 ksi Fy-Stirrups 40.0 ksi
ai
fy-Main Rebar = 60.0 ksi E-Stirrups = 29,000.0 ksi
E-Main Rebar = 29,000.0 ksi Stirrup Bar Size#_ # 3
Number of Resisting Legs Per Stirrup= 2 • •
r
Load Combination ASCE 7-02 bin
36 in
MAD 1.(O.40
r■ _... v ■ ■ ■
N.N
N.
6"w x 16.5"h
Span=12.0 fl
Cross Section&Reinforcing Details
Tee Section, Stem Width=6.0 in, Total Height=16.50 in,Top Flange Width=36.0 in, Flange Thickness=6.0 in
Span#1 Reinforcing....
245 at 1.30 in from Bottom,from 0.0 to 12.0 ft in this span 246 at 1.30 in from Top,from 0.0 to 4.880 ft in this span
246 at 1.30 in from Top,from 7.120 to 12.0 ft in this span
Applied Loads Service loads entered. Load Factors will be applied for calculations.
Load for Span Number 1
Uniform Load: D=0.410, L=0.450 k/ft, Tributary Width=1.0 ft
DESIGN SUMMARY Design OK
Maximum Bending Stress Ratio = 0.259: 1 Maximum Deflection
Section used for this span Typical Section Max Downward L+Lr+S Deflection 0.003 in Ratio= 48754
Mu :Applied -14.544 k-ft Max Upward L+Lr+S Deflection 0.000 in Ratio= 0<360
Mn*Phi:Allowable 56.210 k-ft Max Downward Total Deflection 0.006 in Ratio= 25511
Load Combination +1.20D+0.50Lr+1.60L+1,60H
Max Upward Total Deflection 0.000 in Ratio= 999<180
Location of maximum on span 12.000ft
Span#where maximum occurs Span#1
Cross Section Strength&Inertia Top&Bottom references are for tension side of section
Max Mu (k-ft) Phi"Mn (k-ft) Moment of Inertia (in54)
Cross Section Bar Layout Description Bottom Top Bottom Top I gross Icr-Bottom Icr-Top
Section 1 2-#5 @ d=15.2",2-#6 @ d=1.3", 0.00 0.00 44.81 56.21 4,546.51 1,103.03 1,168.16
Section 2 2-#5 @ d=15.2", 0.00 0.00 41.98 0.00 4,546.51 1,099.27 2.42
Vertical Reactions-Unfactored Support notation:Far left is#1
Load Combination Support 1 Support 2
Overall MAXimum 5.160 5.160
Overall MINimum 2.460 2.460
D Only 2.460 2.460
L Only 2.700 2.700
D+L 5.160 5.160
Shear Stirrup Requirements
Between 0.00 to 1.92 ft, PhiVc/2<Vu<=PhiVc, Req'd Vs=Min 11.4.5.1, use stirrups spaced at 7.000 in
Concrete Beam File=C:1PR0GRA-21ENERCA-1
ENERCALC,INC.1983-2014,Build:6.14.1.26,Ver:6.141.26
Lic.#: KW-06002110 • Licensee:STRUCTURAL CONSULTANTS,INC.
Description: Review capacity of(E)FJ 22
Shear Stirrup Requirements
Between 1.95 to 10.05 ft, Vu<PhiVc/2, Req'd Vs=Not Reqd, use stirrups spaced at 0.000 in
Between 10.08 to 11.97 ft, PhiVc/2<Vu<=PhiVc, Req'd Vs=Min 11.4.5.1, use stirrups spaced at 7.000 in
Overall Maximum Deflections-Unfactored Loads
Load Combination Span Max.""Defl Location in Span Load Combination Max."+"Defl Location in Span
D+L 1 0.0056 6.120 0.0000 0.000
Maximum Deflections for Load Combinations -Unfactored Loads
Load Combination Span Max.Downward Defl Location in Span Max.Upward Def Location in Span
D Only 1 0.0027 6.120 0.0000 0.000
D+L 1 0.0056 6.120 0.0000 0.000
D Only 1 0.0027 6.120 0.0000 0.000
L Only 1 0.0030 6.120 0.0000 0.000
D+L 1 0.0056 6.120 0.0000 0.000
BEAM'--r. --
d.
:� ~-.,
E .9
-15 I I
1.17 2,37 3.57 4.77 5,97 7.17 8,37 9,57 10.77 11.97
Distance(ft)
■+1.405 •+1.2DD+D.SDL,+1.601+1.6DH ■+1 205+1.601+0.505+1 608 •+1 2130+1 601,+0 SOL IN+1.20D+1.60L,+0.80W ■+1.205+D.SDL+1.605
MI+1 205+1.605+6 SOW ■+1.213D+5.501,+D.SOL+1.60W•+1 205+13.SOL+0 505+1.60W ■+1.205+0.SOL+D 205+E •+0,90D+L60W+1,6DH ■+5.955+E+1.60H
7 4.,,„...............
_"•ten
MAIN••.+• - -
5811/.311 ,d
' .-
4
-7 -
1.17 2,37 3,57 4.77 5,97 7.17 8.37 9.57 10,77 11,97
Distance(ft)
■+1.405 ■+1,255+0,501,+I,6DL+1,60H ■+1-2DD+1,601+5.565+1-6OH ■+1,205+1 601,+0.SOL ■+1.205+1.651,+0.8DW ■+1 2DD+0 SDL+1.655
U+1-265+1.605+0.80W ■+1-200+0,561,+0.551+1.60W■+1,205+0-SDL+0.505+1.60W ■+1.205+D.SDL+6-205+E ■+0:96E+L60W+1-60H ■+8 9DD+E+1 6DH
8EA14--». ----.. .............-.....,....... ,,...„.....: ................
_
O,D014
-mow,_ � '
• -0.0029 _. �� � •
O
-0,0043
-0,0058 I �-
0.84 2.04 324 4,44 5,64 6,84 8.04 9.24 10.44 11,64
Distance(ft)
111 60.1y■0+1■1)0.1y■L O„ly■D+L
Concrete Beale File=C:1PROGRA-2\ENERCA--1
ENERCALC,INC.1983-2014,Build:6.14.1.26,Ver:6 14,1.26
Lic.#: KW-06002110 Licensee: STRUCTURAL CONSULTANTS, INC.
Description: Review capacity of(E)2623
CODE REFERENCES
Calculations per
Load Combination Set:ASCE 7-02
Material Properties
f'c1/2 = 4.0 ksi 6 Phi Values Flexure: 0.90
fr= f'c * 7.50 = 474.342 psi Shear: 0.750
yf Density = 145.0 pcf R i = 0.850
X., LtWt Factor = 1.0
Elastic Modulus = 3,122.0 ksi Fy-Stirrups 40.0 ksi - - 1
fy-Main Rebar = 60.0 ksi E-Stirrups = 29,000.0 ksi
E Main Rebar = 29,000.0 ksi Stirrup Bar Size#= # 3 -�,. • • . .,I,
Number of Resisting Legs Per Stirrup= 2 96 in
Load Combination ASCE 7-02
Dry: ;i i r,2)
I • .
1
96"wx16.5"h
Span=25.0 ft
Cross Section&Reinforcing Details
Rectangular Section, Width=96.0 in, Height=16.50 in
Span#1 Reinforcing....
10410 at 1.80 in from Bottom,from 0.0 to 25.0 ft in this span 647 at 1.80 in from Top,from 0.0 to 9.50 ft in this span
447 at 1.80 in from Top,from 0.0 to 9.50 ft in this span 1248 at 1.80 in from Top,from 14.250 to 25.0 ft in this span
Applied Loads Service loads entered Load Factors will be applied for calculations.
Beam self weight calculated and added to loads
Load for Span Number 1
Uniform Load: D=2.560, L=1.420 k/ft, Tributary Width=1.0 ft
DESIGN SUMMARY Desi i n OK
Maximum Bending Stress Ratio = 0.979: 1 Maximum Deflection
Section used for this span Typical Section Max Downward L+Lr+S Deflection 0.048 in Ratio= 6310
Mu :Applied -378.018 k-ft Max Upward L+Lr+S Deflection 0.000 in Ratio= 0<360
Mn*Phi:Allowable 386.045 k-ft Max Downward Total Deflection 0.118 in Ratio= 2538
Load Combination +1,20D+0.50Lr+1.60L+1.60H Max Upward Total Deflection 0.000 in Ratio= 999<180
Location of maximum on span 0.000ft
Span#where maximum occurs Span#1
Cross Section Strength&Inertia Top&Bottom references are for tension side of section
Max Mu (k-ft) Phi*Mn (k-ft) Moment of Inertia (in^4)
Cross Section Bar Layout Description Bottom Top Bottom Top I gross Icr-Bottom Icr-Top
Section 1 10-#10 @ d=14.7",6-#7 @ d=1.8",4-#7 @ d=1.8", 0.00 0.00 776.46 386.05 35,937.00 15,536.52 8,625.65
Section 2 10-#10 @ d=14.7", 0.00 0.00 773.39 0.00 35,937.00 15,094.51 97.75
Section 3 10-#10 @ d=14.7",12-#8 @ d=1.8", 0.00 0.00 776.80 589.47 35,937.00 15,761.78 12,633.64
Vertical Reactions-Unfactored Support notation:Far left is#1
Load Combination Support 1 Support 2
Overall MAXimum 68.855 70.520
Overall MINimum 17.750 17.750
D Only 51.813 52.062
L Only 17.750 17.750
D+L 68.855 70.520
I
.He=C:1PROGRA-2\ENERCA-1 •
Concrete Beam
ENERCALC.INC.1S83-2014.Build:6.14.1,26,Ver:6.14.1.26
Lic.#: KW-06002110 Licensee:STRUCTURAL CONSULTANTS,INC.
Description: Review capacity of(E)2B23
Shear Stirrup Requirements
Entire Beam Span Length:PhiVc/2<Vu<=PhiVc, Req'd Vs=Not Reqd 11.5.6.1, use stirrups spaced at 0.000 in
Overall Maximum Deflections-Unfactored Loads
Load Combination Span Max."2 Def Location in Span Load Combination Max."+"Defl Location in Span
D+L 1 0.1182 12.250 0.0000 0.000
Maximum Deflections for Load Combinations -Unfactored Loads
Load Combination Span Max.Downward Defl Location in Span Max.Upward Defl Location in Span
D Only 1 0.0707 12.250 0.0000 0.000
D+L 1 0.1182 12.250 0.0000 0.000
D Only 1 0.0707 12.250 0.0000 0.000
L Only 1 0.0222 12.750 0.0000 0.000
D+L 1 0.1182 12.250 0.0000 0.000
193
48 W
BEAM-•-a. A .. w w
u
i' -241
-386 +
2.44 4.94 7.44 9.94 12.44 14.94 17.44 19.94 22.44 24,94
Distance(Ft)
•+1406 ■+1,2OD+O,SDL.+1.60L+1,608 ■+1.266+1,6OL+6,505+1,6011 ■+1.266+1.60L.+O.SOL ■+L 266+1.60L.+9 BDW ■+1 zoo+D.59L+1.665
M+1 269+1 605+6 SOW ■+1 206+D.SDL,+6-SDL+1-66W■+1.266+D.SDL+6.SDS+1.66W ■+1.269+O.SDL+6.215+E ■+0.9OD+1.66W+1-668 •+0.966+E+1.6011
93 (
r
Y� BEAM..n. A
n3
0
L
46 __
93 _ I i
2.44 4,94 7.44 9.94 12.44 14.94 17.44 19.94 22.44 24,94
Distance(Ft)
•+14DD ■+1 ZOD+D SDL.+1 60L+1.6011 •+1 26D+1-66L+D.525+1 6011 ■+1 200+1 6DL,+13 SOL ■+1.2DD+1.60L,+O SOW ■+1 206+D SOL+1 605
II+1 205+1 665+0 SOW ■+1 206+13 SDL.+6 56L+1,60W■+5 215D+D.56L+6,565+1 DOW •+1 2DD+D.SDL+O 2DS+E ■+0.905+1 66W+1,668 ■+D 9DD+E+1 60H
0.03 _
c -0.06 -
............„..........................„7----., ----...•
al -
-0.09
0.12 T
1,75 4.25 6.75 9.25 11,75 14,25 16,75 19.25 21,75 2425
Distance(Ft)
•DOnly■D+L■DOnly■LOnly■D+L
Concrete Beam File=C:IPROGRA-21ENERCA-1
ENERCALC,INC.1983-2014,Build:6.14.6.15.Ver6 14.6 15
Lic.#:KW-06002110 Licensee:STRUCTURAL CONSULTANTS, INC.
Description: (E)2B23 w/added AD7 load
CODE REFERENCES
Calculations per
Load Combination Set : ASCE 7-02
Material Properties
f'c1/2 4.0 ksi 6 Phi Values Flexure: 0.90
fr= fc * 7.50 = 474.342 psi Shear: 0.750
W Density = 145.0 pcf R 1 = 0.850
A, LtWt Factor = 1.0
Elastic Modulus = 3,122.0 ksi Fy-Stirrups 40.0 ksi -
fy-Main Rebar = 60.0 ksi E-Stirrups = 29,000.0 ksi
E Main Rebar = 29,000.0 ksi Stirrup Bar Size#= # 3 * • . •
Number of Resisting Legs Per Stirrup= 2 96 in
Load Combination ASCE 7-02
D(1 693)
-..... 072 5811(1 16
•
96"wx 16.5"h
Span=25.0 ft
Cross Section&Reinforcing Details
Rectangular Section, Width=96.0 in, Height=16.50 in
Span#1 Reinforcing....
10410 at 1.80 in from Bottom,from 0.0 to 25.0 ft in this span 447 at 1.80 in from Top,from 0.0 to 9.50 ft in this span
647 at 1.80 in from Top,from 0.0 to 9.50 ft in this span 1248 at 1.80 in from Top,from 14.250 to 25.0 ft in this span
Applied Loads Service loads entered. Load Factors will be applied for calculations.
Beam self weight calculated and added to loads
Load for Span Number 1
Uniform Load: D=2.560, L=1.180 k/ft, Tributary Width=1.0 ft
Point Load: D=1.693kt7a,12.50ft
DESIGN SUMMARY Desi•n OK
Maximum Bending Stress Ratio = 0.944: 1 Maximum Deflection
Section used for this span Typical Section Max Downward L+Lr+S Deflection 0.040 in Ratio= 7591
Mu :Applied -364.367 k-ft Max Upward L+Lr+S Deflection 0.000 in Ratio= 0<360
Mn*Phi:Allowable 386.045 k-ft Max Downward Total Deflection 0.114 in Ratio= 2637
Max Upward Total Deflection 0.000 in Ratio= 999<180
Load Combination +1.20D+0.50Lr+1.60L+1.60H
Location of maximum on span 0.000ft
Span#where maximum occurs Span#1
Cross Section Strength&Inertia Top&Bottom references are for tension side of section
Max Mu (k-ft) Phi*Mn (k-ft) Moment of Inertia (inA4)
Cross Section Bar Layout Description Bottom Top Bottom Top I gross la:-Bottom Icr-Top
Section 1 10-#10 @ d=14.7",4-#7 @ d=1.8",6-#7 @ d=1.8", 0.00 0.00 776.46 386.05 35,937.00 15,536.52 8,625.65
Section 2 10-#10 @ d=14.7", 0.00 0.00 773.39 0.00 35,937.00 15,094.51 97.75
Section 3 10-#10 @ d=14.7",12-#8 @ d=1.8", 0.00 0.00 776.80 589.47 35,937.00 15,761.78 12,633.64
Vertical Reactions-Unfactored Support notation:Far left is#1
Load Combination Support 1 Support 2
Overall MAXimum 66.780 68.288
Overall MINimum 14.750 14,750
D Only 52.623 52.945
L Only 14.750 14.750
D+L 66.780 68.288
Concrete B@8111 File=C:IPROGRA-21ENERCA-1
ENERCALC,INC.1963-2014,Build:6.14.6.15,Ver:6.14.6.15
•Lic..# KLVV-06Q021.10+ m Licensee:STRUCTURAL CONSULTANTS,INC.
Description: (E)2B23 w/added AD7 load
Shear Stirrup Requirements _
Entire Beam Span Length:PhiVc/2<Vu<=PhiVc, Req'd Vs=H<0.5W,Not Reqd, use stirrups spaced at 0.000 in
Overall Maximum Deflections-Unfactored Loads
Load Combination Span Max."-'Defl Location in Span Load Combination Max."+"Defl Location in Span
D+L 1 0.1138 12.250 0.0000 0.000
Maximum Deflections for Load Combinations -Unfactored Loads
Load Combination Span Max.Downward Defl Location in Span Max.Upward Defl Location in Span
D Only 1 0.0742 12.250 0.0000 0.000
D+L 1 0.1138 12.250 0.0000 0.000
D Only 1 0.0742 12.250 0.0000 0.000
L Only 1 0.0185 12.750 0.0000 0.000
D+L 1 0.1138 12.250 0 0000 0.000
189 •
49 - - -
C -91 r� J
E
231 .�
-372
2.44 4.94 7.44 9.94 12.44 14.94 17.44 19.94 22.44 2494
Distance(ft)
•+1455 ■+1 255+5 SDL.+1 681+1 655 ■+1 205+1 60L+D.SDS+1,6011 •+1.20D+1.6DL,+0.5DL ■+1-215D+1-602.+0_80W ■+1.205+0.SDL+1-605
•+1 205+1 605+0 SOW ■+1 206+D.SDL.+0.50L+1.60W■+1 205+D.SOL+O.S05+1-60W ■+1.20D+0-50L+D-205+E ■+0-806+1-6DW+1-66H ■+0_955+E+1-608
89 ,
44 -•-
eEN 1- _ 1
A
DL'I
-44 ^� _
-89 --
2.44 4.94 7.44 9.94 12.44 14.94 17.44 19.94 22.44 24.94
Distance(ft)
•+1405 ■+1.255+D.SOL.+1 60L+1.605 ■+1,205+1.6DL+0.5D5+1.605 •+1.20D+1.602.+O.SDL •+1.LDD+1.652.+D.BDW In+1,205+0,502+1 601
■+1 256+1 651+0 80W ■+1,205+0,8OL.+O,SOL+1.6DW■+1.265+0-5.0L+DS0s+1.60W ■+1.2DD+O-SDL+0.205+E •+0_905+1_60W+1-605 ■+6.90D+E+1-605
BEAM---»
F'
0.03
•0,06 .``
-0,09 ..._.
.0.12
1.75 4.25 6.75 925 11.75 14.25 16,75 19.25 21.75 24.25
Distance(ft)
•D O..Iy■D+L•D O..ly■L Only■D+L
Concrete Beam File=C:1PROGRA'-21ENERCA-1
ENERCALC,INC.1983-2014,Build:6.14.6.15,Ver:6.14.6.15
Lic.#: KW-06002110 Licensee:STRUCTURAL CONSULTANTS, INC.
Description: (E)FJ21 w/added ECU loading
CODE REFERENCES
Calculations per
Load Combination Set:ASCE 7-02
Material Properties
fc112 = 4.0 ksi 6 Phi Values Flexure: 0.90
•
•
fr= fc * 7.50 = 474.342 psi Shear: 0.750 I • • N
yf Density = 145.0 pcf R 1 = 0.850 I - - 1
T, LtWt Factor = 1.0
Elastic Modulus = 3,122.0 ksi Fy-Stirrups 40.0 ksi
fy-Main Rebar = 60.0 ksi E-Stirrups = 29,000.0 ksi
E-Main Rebar = 29,000.0 ksi Stirrup Bar Size#_ # 3
Number of Resisting Legs Per Stirrup= 2 • •
Load Combination ASCE 7-02 ' 6 in '
36 in
mr0.19}
♦ V •
D[Q.411 LIQ•191
7 ■ ■
6"wx 165"h
Span=19.50 ft
Cross Section&Reinforcing Details
Tee Section, Stem Width=6.0 in, Total Height=16.50 in,Top Flange Width=36.0 in, Flange Thickness=4.50 in
Span#1 Reinforcing....
246 at 1.30 in from Bottom,from 0.0 to 19.50 ft in this span 246 at 1.30 in from Top,from 14.60 to 19.50 ft in this span
245 at 1.30 in from Top,from 0.0 to 6.50 ft in this span
Applied Loads Service loads entered Load Factors will be applied for calculations.
Load for Span Number 1
Uniform Load: D=0.410, L=0.180 k/ft, Tributary Width=1.0 ft
Uniform Load: D=0.190 k/ft,Extent=0.0-->>4.0 ft, Tributary Width=1.0 ft
DESIGN SUMMARY Desi•n OK
Maximum Bending Stress Ratio = 0.651 : 1 Maximum Deflection
Section used for this span Typical Section Max Downward L+Lr+S Deflection 0.011 in Ratio= 20932
Mu:Applied -26.080 k-ft Max Upward L+Lr+S Deflection 0.000 in Ratio= 0<360
Mn*Phi:Allowable 40.074 k-ft Max Downward Total Deflection 0.030 in Ratio= 7672
Load Combination +1.20D+0.50Lr+1.60L+1.60H
Max Upward Total Deflection 0.000 in Ratio= 999<180
Location of maximum on span 0.000ft
Span#where maximum occurs Span#1
Cross Section Strength&Inertia Top&Bottom references are for tension side of section
Max Mu (k-ft) Phi*Mn (k-ft) Moment of Inertia (in"4)
Cross Section Bar Layout Description Bottom Top Bottom Top I gross Icr-Bottom Icr-Top
Section 1 2-#6 @ d=15.2",2-#5 @ d=1.3", 0.00 0.00 61.11 40.07 4,530.03 1,511.16 903.32
Section 2 2-#6 @ d=15.2", 0.00 0.00 59 34 0.00 4,530.03 1,505.15 2.78
Section 3 2-#6 @ d=15.2",2-#6 @ d=1.3", 0.00 0.00 61.36 56.29 4,530.03 1,513.50 1,192.55
Vertical Reactions-Unfactored Support notation:Far left is#1
Load Combination Support 1 Support 2
Overall MAXimum 6.443 5.822
Overall MINimum 1.755 1.755
D Only 4.729 4,026
L Only 1.755 1.755
D+L 6.443 5.822
Concrete Beam File=C3PROGRA-21ENERCA--1
ENERCALC,INC.1983-2014.Build:6,14,6,35,Ver:6.148.15
Lic.#: KW-06002110 Licensee:STRUCTURAL CONSULTANTS, INC.
Description: (E)FJ21 w/added FCU loading
Shear Stirrup Requirements
Between 0.00 to 3.73 ft, PhiVc/2<Vu<=PhiVc, Req'd Vs=Min 11.4.5.1, use stirrups spaced at 7.000 in
Between 3.77 to 15.69 ft, Vu<PhiVc/2, Req'd Vs=Not Reqd 11.4.6.1, use stirrups spaced at 0.000 in
Between 15.73 to 19.46 ft, PhiVcl2<Vu<=PhiVc, Req'd Vs=Min 11.4.5.1, use stirrups spaced at 7.000 in
Overall Maximum Deflections-Unfactored Loads
Load Combination Span Max."-"Defl Location in Span Load Combination Max."+"Defl Location in Span
D+L t 0.0305 9.555 00000 0000
Maximum Deflections for Load Combinations -Unfactored Loads
Load Combination Span Max.Downward Defl Location in Span Max.Upward Defl Location in Span
D Only 1 0.0193 9.555 0.0000 0.000
D+L 1 0.0305 9.555 0.0000 0.000
D Only 1 0.0193 9.555 0.0000 0.000
L Only 1 0.0083 9.945 0.0000 0.000
D+L 1 0.0305 9.555 0.0000 0.000
13
3 ._
5E Ai,1... `
17
-27 t I I
1.91 3.86 5.81 7,76 9.71 11,66 13,61 15.56 17.51 1946
Distance(ft)
•+1..150 ■+1.20D+0.55L.+1.60L+1.60H ■+1 213D+1,60L+5.5135+1 658 ■+1.205+I.60L,+5.50L ■+1.250+1.601.+0 55W ■+1.20D+13.50L+1 605
■+1 205+1.655+6.80W ■+1.2DD+5-SOL.+D.50L+1.60W•+1 2DD+O.50L+5.555+1,61W M+1.55065.581+5.555,5 ■+5.950+1 65W+1.656 ■+5 9DD+E+1-606
4
5
2' t
6Ept,7...,y .��o��
m
L
tn
-Q J .,
1.91 3.86 5.81 7.76 9.71 11.66 13.61 15.56 17.51 19,46
Distance(ft)
•+140D ■+1 211D+0.50L.+1 601+1.656 ■+1.200+1.60L+D 5135+1 65H ■+1 2DD+1 600+0.50L •+1 255+1 600+0 SOW ■+1.20D+D,5DL+1.655
•+1 250+1 605+5 817W ■+1 20D+0 SDL.+S-55L+1 6DW•+1 250+5 561+0 505+1 60W •+1 250+0.SSL+0.205+E •+D 9DD+1 65W+1.65H ■+0-9DD+E+1,6136
BEAM ,.-›. . .
�
�
-0.008 \ � :
c -0.016
-0,023 ..___
-0.031 L
1.37 3.32 5.27 7.22 9.17 11,12 13.07 15.02 16.97 18,92
Distance(ft)
IN D Only■D+L IN D O..Iy•L Only■D+L
ui -
s. 3 3
�a
N •O •O n CO .O v) m M u
I
\ .° h < M N 0 CO m n n -u O P O N n C) 0 P W 0• 0 — .0 O 0 M M u)
✓ Pn P co n '1 -0 CO co N ' 0 0 P co n
vyF -0 CO
W mm -4 co a o e m m O. O N M
M - nv
M N O P n •O - M 0 P m n n .O n M
N N N N 3
0)
w .. .__... O hOO. �k" °
In co 0 0 Lo U) -0 d)
Zg . R co n c0c0W n n ° c•�
i �Q N M °,
V I -.. M
u O.
L W u .p .O N
R. P CO n .0 O O P m n V W M ^ O O P W n •o h
^
L. °
In 3▪ O o ZM
v
ZJ dIx .O V M N M P n •O N N. o. � p � v n N CO •o un v o n v1 o a u1 v y
Vv •O h `Q co O P COm n �O .O oU N co m o., P CO 0 h M N O 0 m n •O va Vco
O 2-13Op N EO
HZO d 7 ° '.4. •OO ,_ M •ON O n n n .m OM . O M R .°
H— Q' N ON P _ ^ ^ ---- E
CI-
T
a W n n o o n v v 5
v-
W I• .Q 0 IX s-
N 2 a m m h COmW n .- •no NI h O m - L O
Z 0 > , m I v) O m N N M n O co o.M O co
W a to CC ii: sy O •O N Ln O P P CO n .O n N 0 CO
h .O CO h •O oo .O N n ^ v
U H O M N o o P W n •O b h er Q }
Z O O m v m v O P O M p O w
O G y C \ •O m •O co P •O v n n N N COMak n •O v M O P n 0 .O N v M N -O p
(.� �k 4 CO n 0n v M — O P u ° .-
1.1.1
W O IE
N co M h N ' a coMCO N CO M n.O�/) n n �") 0 O. a00 h R a P'7
v
c
.n-. r co M
'" O CO N N CO lO m n .O•O� co .O — m .o h •o n 0 >
p •° •O P CO n �O co M M •� N O P n •o v1 -0 CO 0
�k�k�k -� �k�k .,(1-)
p
O h - h O W
E — _ > >
15 O O O N M V N `° N co P 0 N M sr v) •O N m 0
CO m CO N N N N N N N N M M CO CO M M M CO M 0 O O M d' h •O n W 0. 0 r- N 01) .0 v1 .O n m P I-Q
LL N O. m m m N N N N N N N M M M M M M CO co co M
.F. O i H „C N E ` a
O m°1- 4 1.4!/1 uodg d ,' z r 1:1. {A u!,!uodg
— cm NI m O ^ n ° o
'V _
P P h n N. N CO
P O P n ^ O P P
CO 04
1.1>I v) v) .n N. n •o '�) CO COMI°. N
h N. 0 `7 m co 0 co P P h •O h co N O
el o\ O P P m n •O •O h
u
O M
M — o) `d d' n N CO `o co co v O 0 CO O. O N v1 m
CJ U ' N N u'1 P •O '0 co co coP m so N N R M cog P m n n so co O co n •o M ' 0 CO
0 m $ n •O in N O CO •O h M N O m n N N N N N
N — --_.. ..�. -...--_. n
0 a
s. m m h 0. v V) ,D °
.0 p 0.0 h v co P OO CO N
O.
VS M N `
Z C Is. m .O P N .O m P N y'0
6 v) n P N •O n CO O M 01 O N O O P m n n O C
0 O Y) M ^�k�k O P co m n .co u) L') M M - O
Cr
W u O.`
U LL a M W x d
�,• n ,. u W .O h CO N N M O OD n m n n .MO h 0 0
W \ N h co •O ^ P n •O •O m 0 M Or M W CO h n .O h co N O P
1�-LIJ O rn V V m o h M N P co n o v1 at R t7 ui
n Z -o
to-� O o Z 11 p N o o
Z 7 a O U W n.O O O M CO P N •o ^ v1 m m m o N of m N n
• IU ol CO n •n co .O N )° N .0 N .O CO ak�k ^ ^ ^ ^ o 0 m n n ,O h R V' co
N P CO n •O u1 Q M M \ -°i N N N co •O h M W ..
C
Z 0 N I < • a
71 O O M O. h a M R •O 0. M m M P n L
00.E
Q - + h ^ O m n b h R M vi .tee CO 03 Lo. m m n n •O •O h N
W >Z O
Q o
e) `L ,0 CV
a °
cr—
°
m O P : m R OM d
N
W Q ^ O0 n .O 0 p) 3 a
ZO ° N
N o m w▪ w
Hc O h h ^ 0001nhvM ° •OOP coo int, vPnaarlM °V
OQ u 0 00 n 'O ua M u N G
W xco v v1 a h m o a m N
co M W n h C'' n•O v1 V) N N vl O 0 m n 1O v) VI v co co c 1V
P n y
O n
O h O t
O O P M m 0 M N .o a Q7. >
.p 4 VS i .O•O o ' ^ ^ P co n 0O
O O h M �k�k�k 'fl c
1.
�n N O
0 0 0 N M h •O n co P O N co h •O n W O O O _ N M N `O n CO Co O 01 N CO v u1 •O n m .a
0 m m m N N N N N N N N N co co co co co co co co co m m m N N N N N N N N N M M CO M M M M M M
d
H Q
0
o ~ Z. 2F-
-. °~ ° °~
o ms.j ui,!uodg o Waj ui,1 uods
I